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x^2+11x+11=4x
We move all terms to the left:
x^2+11x+11-(4x)=0
We add all the numbers together, and all the variables
x^2+7x+11=0
a = 1; b = 7; c = +11;
Δ = b2-4ac
Δ = 72-4·1·11
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{5}}{2*1}=\frac{-7-\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{5}}{2*1}=\frac{-7+\sqrt{5}}{2} $
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